#유코딩 코딩연습장
7. Reverse Integer 본문
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123 Output: 321
Example 2:
Input: x = -123 Output: -321
Example 3:
Input: x = 120 Output: 21
Example 4:
Input: x = 0 Output: 0
class Solution {
public:
int reverse(int x) {
long long temp = 0;
while(x)
{
if( temp *10 > INT_MAX | temp * 10 < INT_MIN)
return 0;
temp = temp * 10 + x % 10;
x /= 10;
}
return temp;
}
};
'#LeetCode > Easy' 카테고리의 다른 글
35. Search Insert Position (0) | 2021.07.23 |
---|---|
9. Palindrome Number (0) | 2021.07.23 |
1. Two Sum (0) | 2021.07.22 |
Comments